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3.Trigonometrical Ratios, Functions and Identities
normal
જો $3\cos \theta + 4\sin \theta = 5$ અને $3\sin \theta - 4\cos \theta $ =
A
$1$
B
$-1$
C
$0$
D
$\frac {1}{2}$
Solution
$3\cos \theta + 4\sin \theta = 5$ and $3\sin \theta – 4\cos \theta = x$ Square and add $x^2 = 0$
Standard 11
Mathematics