જો $3\cos \theta + 4\sin \theta = 5$ અને $3\sin \theta - 4\cos \theta $ =
જો $3\cos \theta + 4\sin \theta = 5$ અને $3\sin \theta - 4\cos \theta $ =
- A
$1$
- B
$-1$
- C
$0$
- D
$\frac {1}{2}$
Similar Questions
જો $\alpha + \beta = \frac{\pi }{2}$ અને $\beta + \gamma = \alpha ,$ તો $\tan \,\alpha $ મેળવો.
જો $\alpha + \beta = \frac{\pi }{2}$ અને $\beta + \gamma = \alpha ,$ તો $\tan \,\alpha $ મેળવો.
- [IIT 2001]
$\frac{{3 + \cot {{76}^o}\cot {{16}^o}}}{{\cot {{76}^o} + \cot {{16}^o}}}$ =
$\frac{{3 + \cot {{76}^o}\cot {{16}^o}}}{{\cot {{76}^o} + \cot {{16}^o}}}$ =
$\frac{{\tan \,\left( {{\textstyle{{3\,\pi } \over 2}}\,\, - \,\,\alpha } \right)\,\,\,\cos \,\left( {{\textstyle{{3\,\pi } \over 2}}\,\, - \,\,\alpha } \right)}}{{\cos \,(2\,\pi \,\, - \,\alpha )}}$ $+ cos \left( {\alpha \,\, - \,\,\frac{\pi }{2}} \right) \,sin (\pi -\alpha ) + cos (\pi +\alpha ) sin \,\left( {\alpha \,\, - \,\,\frac{\pi }{2}} \right)$ =
$\frac{{\tan \,\left( {{\textstyle{{3\,\pi } \over 2}}\,\, - \,\,\alpha } \right)\,\,\,\cos \,\left( {{\textstyle{{3\,\pi } \over 2}}\,\, - \,\,\alpha } \right)}}{{\cos \,(2\,\pi \,\, - \,\alpha )}}$ $+ cos \left( {\alpha \,\, - \,\,\frac{\pi }{2}} \right) \,sin (\pi -\alpha ) + cos (\pi +\alpha ) sin \,\left( {\alpha \,\, - \,\,\frac{\pi }{2}} \right)$ =
સાબિત કરો કે : $\frac{\cos 9 x-\cos 5 x}{\sin 17 x-\sin 3 x}=-\frac{\sin 2 x}{\cos 10 x}$
સાબિત કરો કે : $\frac{\cos 9 x-\cos 5 x}{\sin 17 x-\sin 3 x}=-\frac{\sin 2 x}{\cos 10 x}$
$\sin {20^o}\,\sin {40^o}\,\sin {60^o}\,\sin {80^o} = $
$\sin {20^o}\,\sin {40^o}\,\sin {60^o}\,\sin {80^o} = $